Integrand size = 23, antiderivative size = 162 \[ \int \frac {a+b \log \left (c x^n\right )}{x^3 \left (d+e x^2\right )^3} \, dx=-\frac {3 b n}{4 d^3 x^2}+\frac {a+b \log \left (c x^n\right )}{4 d x^2 \left (d+e x^2\right )^2}+\frac {6 a-b n+6 b \log \left (c x^n\right )}{8 d^2 x^2 \left (d+e x^2\right )}-\frac {12 a-5 b n+12 b \log \left (c x^n\right )}{8 d^3 x^2}+\frac {e \log \left (1+\frac {d}{e x^2}\right ) \left (12 a-5 b n+12 b \log \left (c x^n\right )\right )}{8 d^4}-\frac {3 b e n \operatorname {PolyLog}\left (2,-\frac {d}{e x^2}\right )}{4 d^4} \]
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Time = 0.22 (sec) , antiderivative size = 162, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.217, Rules used = {2385, 2380, 2341, 2379, 2438} \[ \int \frac {a+b \log \left (c x^n\right )}{x^3 \left (d+e x^2\right )^3} \, dx=\frac {e \log \left (\frac {d}{e x^2}+1\right ) \left (12 a+12 b \log \left (c x^n\right )-5 b n\right )}{8 d^4}-\frac {12 a+12 b \log \left (c x^n\right )-5 b n}{8 d^3 x^2}+\frac {6 a+6 b \log \left (c x^n\right )-b n}{8 d^2 x^2 \left (d+e x^2\right )}+\frac {a+b \log \left (c x^n\right )}{4 d x^2 \left (d+e x^2\right )^2}-\frac {3 b e n \operatorname {PolyLog}\left (2,-\frac {d}{e x^2}\right )}{4 d^4}-\frac {3 b n}{4 d^3 x^2} \]
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Rule 2341
Rule 2379
Rule 2380
Rule 2385
Rule 2438
Rubi steps \begin{align*} \text {integral}& = \frac {a+b \log \left (c x^n\right )}{4 d x^2 \left (d+e x^2\right )^2}-\frac {\int \frac {-6 a+b n-6 b \log \left (c x^n\right )}{x^3 \left (d+e x^2\right )^2} \, dx}{4 d} \\ & = \frac {a+b \log \left (c x^n\right )}{4 d x^2 \left (d+e x^2\right )^2}+\frac {6 a-b n+6 b \log \left (c x^n\right )}{8 d^2 x^2 \left (d+e x^2\right )}+\frac {\int \frac {-6 b n-4 (-6 a+b n)+24 b \log \left (c x^n\right )}{x^3 \left (d+e x^2\right )} \, dx}{8 d^2} \\ & = \frac {a+b \log \left (c x^n\right )}{4 d x^2 \left (d+e x^2\right )^2}+\frac {6 a-b n+6 b \log \left (c x^n\right )}{8 d^2 x^2 \left (d+e x^2\right )}+\frac {\int \frac {-6 b n-4 (-6 a+b n)+24 b \log \left (c x^n\right )}{x^3} \, dx}{8 d^3}-\frac {e \int \frac {-6 b n-4 (-6 a+b n)+24 b \log \left (c x^n\right )}{x \left (d+e x^2\right )} \, dx}{8 d^3} \\ & = -\frac {3 b n}{4 d^3 x^2}+\frac {a+b \log \left (c x^n\right )}{4 d x^2 \left (d+e x^2\right )^2}+\frac {6 a-b n+6 b \log \left (c x^n\right )}{8 d^2 x^2 \left (d+e x^2\right )}-\frac {12 a-5 b n+12 b \log \left (c x^n\right )}{8 d^3 x^2}+\frac {e \log \left (1+\frac {d}{e x^2}\right ) \left (12 a-5 b n+12 b \log \left (c x^n\right )\right )}{8 d^4}-\frac {(3 b e n) \int \frac {\log \left (1+\frac {d}{e x^2}\right )}{x} \, dx}{2 d^4} \\ & = -\frac {3 b n}{4 d^3 x^2}+\frac {a+b \log \left (c x^n\right )}{4 d x^2 \left (d+e x^2\right )^2}+\frac {6 a-b n+6 b \log \left (c x^n\right )}{8 d^2 x^2 \left (d+e x^2\right )}-\frac {12 a-5 b n+12 b \log \left (c x^n\right )}{8 d^3 x^2}+\frac {e \log \left (1+\frac {d}{e x^2}\right ) \left (12 a-5 b n+12 b \log \left (c x^n\right )\right )}{8 d^4}-\frac {3 b e n \text {Li}_2\left (-\frac {d}{e x^2}\right )}{4 d^4} \\ \end{align*}
Result contains complex when optimal does not.
Time = 0.73 (sec) , antiderivative size = 507, normalized size of antiderivative = 3.13 \[ \int \frac {a+b \log \left (c x^n\right )}{x^3 \left (d+e x^2\right )^3} \, dx=\frac {-\frac {8 d \left (a-b n \log (x)+b \log \left (c x^n\right )\right )}{x^2}-\frac {4 d^2 e \left (a-b n \log (x)+b \log \left (c x^n\right )\right )}{\left (d+e x^2\right )^2}-\frac {16 d e \left (a-b n \log (x)+b \log \left (c x^n\right )\right )}{d+e x^2}-48 e \log (x) \left (a-b n \log (x)+b \log \left (c x^n\right )\right )+24 e \left (a-b n \log (x)+b \log \left (c x^n\right )\right ) \log \left (d+e x^2\right )+b n \left (\frac {9 e^{3/2} x \log (x)}{-i \sqrt {d}+\sqrt {e} x}-24 e \log ^2(x)-\frac {4 d (1+2 \log (x))}{x^2}+e \left (\frac {d}{d+i \sqrt {d} \sqrt {e} x}+\log (x)-\frac {d \log (x)}{\left (\sqrt {d}+i \sqrt {e} x\right )^2}-\log \left (i \sqrt {d}-\sqrt {e} x\right )\right )-9 e \log \left (i \sqrt {d}-\sqrt {e} x\right )+e \left (\frac {d}{d-i \sqrt {d} \sqrt {e} x}+\log (x)-\frac {d \log (x)}{\left (\sqrt {d}-i \sqrt {e} x\right )^2}-\log \left (i \sqrt {d}+\sqrt {e} x\right )\right )+\frac {-9 i e^{3/2} x \log (x)+9 i e \left (i \sqrt {d}+\sqrt {e} x\right ) \log \left (i \sqrt {d}+\sqrt {e} x\right )}{\sqrt {d}-i \sqrt {e} x}+24 e \left (\log (x) \log \left (1+\frac {i \sqrt {e} x}{\sqrt {d}}\right )+\operatorname {PolyLog}\left (2,-\frac {i \sqrt {e} x}{\sqrt {d}}\right )\right )+24 e \left (\log (x) \log \left (1-\frac {i \sqrt {e} x}{\sqrt {d}}\right )+\operatorname {PolyLog}\left (2,\frac {i \sqrt {e} x}{\sqrt {d}}\right )\right )\right )}{16 d^4} \]
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Result contains higher order function than in optimal. Order 9 vs. order 4.
Time = 1.18 (sec) , antiderivative size = 440, normalized size of antiderivative = 2.72
method | result | size |
risch | \(-\frac {b \ln \left (x^{n}\right ) e}{4 d^{2} \left (e \,x^{2}+d \right )^{2}}+\frac {3 b \ln \left (x^{n}\right ) e \ln \left (e \,x^{2}+d \right )}{2 d^{4}}-\frac {b \ln \left (x^{n}\right ) e}{d^{3} \left (e \,x^{2}+d \right )}-\frac {b \ln \left (x^{n}\right )}{2 d^{3} x^{2}}-\frac {3 b \ln \left (x^{n}\right ) e \ln \left (x \right )}{d^{4}}+\frac {3 b n e \ln \left (x \right )^{2}}{2 d^{4}}-\frac {3 b n e \ln \left (x \right ) \ln \left (e \,x^{2}+d \right )}{2 d^{4}}+\frac {3 b n e \ln \left (x \right ) \ln \left (\frac {-e x +\sqrt {-d e}}{\sqrt {-d e}}\right )}{2 d^{4}}+\frac {3 b n e \ln \left (x \right ) \ln \left (\frac {e x +\sqrt {-d e}}{\sqrt {-d e}}\right )}{2 d^{4}}+\frac {3 b n e \operatorname {dilog}\left (\frac {-e x +\sqrt {-d e}}{\sqrt {-d e}}\right )}{2 d^{4}}+\frac {3 b n e \operatorname {dilog}\left (\frac {e x +\sqrt {-d e}}{\sqrt {-d e}}\right )}{2 d^{4}}-\frac {5 b n e \ln \left (e \,x^{2}+d \right )}{8 d^{4}}+\frac {b n e}{8 d^{3} \left (e \,x^{2}+d \right )}-\frac {b n}{4 d^{3} x^{2}}+\frac {5 b e n \ln \left (x \right )}{4 d^{4}}+\left (-\frac {i b \pi \,\operatorname {csgn}\left (i c \right ) \operatorname {csgn}\left (i x^{n}\right ) \operatorname {csgn}\left (i c \,x^{n}\right )}{2}+\frac {i b \pi \,\operatorname {csgn}\left (i c \right ) \operatorname {csgn}\left (i c \,x^{n}\right )^{2}}{2}+\frac {i b \pi \,\operatorname {csgn}\left (i x^{n}\right ) \operatorname {csgn}\left (i c \,x^{n}\right )^{2}}{2}-\frac {i b \pi \operatorname {csgn}\left (i c \,x^{n}\right )^{3}}{2}+b \ln \left (c \right )+a \right ) \left (\frac {e^{2} \left (-\frac {d^{2}}{2 e \left (e \,x^{2}+d \right )^{2}}+\frac {3 \ln \left (e \,x^{2}+d \right )}{e}-\frac {2 d}{e \left (e \,x^{2}+d \right )}\right )}{2 d^{4}}-\frac {1}{2 d^{3} x^{2}}-\frac {3 e \ln \left (x \right )}{d^{4}}\right )\) | \(440\) |
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\[ \int \frac {a+b \log \left (c x^n\right )}{x^3 \left (d+e x^2\right )^3} \, dx=\int { \frac {b \log \left (c x^{n}\right ) + a}{{\left (e x^{2} + d\right )}^{3} x^{3}} \,d x } \]
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Timed out. \[ \int \frac {a+b \log \left (c x^n\right )}{x^3 \left (d+e x^2\right )^3} \, dx=\text {Timed out} \]
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\[ \int \frac {a+b \log \left (c x^n\right )}{x^3 \left (d+e x^2\right )^3} \, dx=\int { \frac {b \log \left (c x^{n}\right ) + a}{{\left (e x^{2} + d\right )}^{3} x^{3}} \,d x } \]
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\[ \int \frac {a+b \log \left (c x^n\right )}{x^3 \left (d+e x^2\right )^3} \, dx=\int { \frac {b \log \left (c x^{n}\right ) + a}{{\left (e x^{2} + d\right )}^{3} x^{3}} \,d x } \]
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Timed out. \[ \int \frac {a+b \log \left (c x^n\right )}{x^3 \left (d+e x^2\right )^3} \, dx=\int \frac {a+b\,\ln \left (c\,x^n\right )}{x^3\,{\left (e\,x^2+d\right )}^3} \,d x \]
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